How do you convert $9.8 \times 10^{3}$ $9.8 xx 10^3$ $μ m/ms$ $mu"m/ms"$ to $m/s$ $"m/s"$ ?

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Answer 1 · 2015-09-12T18:50:58

$9.8 m/s$ $9.8"m/s"$

The 2 conversion factors to use are:

$1 μ m = 10^{- 6} m$ $1mu"m"=10^(-6)"m"$

and

$1 ms = 10^{- 3} s$ $1"ms"=10^(-3)"s"$

So:

$9.8 \times 10^{3} μ m/ms = 9.8 \times 10^{3} \times 10^{- 6} m/ms$ $9.8xx10^3mu"m/ms"=9.8xx10^3xx10^(-6)"m/ms"$

$= 9.8 \times 10^{3} \times 10^{- 6} \times 10^{3} m/s$ $=9.8xx10^3xx10^(-6)xx10^(3)"m/s"$

$= 9.8 m/s$ $=9.8"m/s"$

How do you convert 9.8×1039.8 xx 10^3 μm/msmu"m/ms" to m/s"m/s"?