How do you convert #8 - 15i# to polar form?
1 Answer
May 6, 2017
Explanation:
#"to convert from "color(blue)"cartesian to polar form"#
#"that is " (x,y)to(r,theta)" where"#
#• r=sqrt(x^2+y^2)#
#• theta=tan^-1(y/x); -pi < theta <= pi#
#"here " (x,y)=(8,-15)#
#rArrr=sqrt(8^2+(-15)^2)=17#
#"now " 8-15i" is in the fourth quadrant so we must ensure"#
#"that "theta" is in the fourth quadrant"#
#theta=tan^-1(-15/8)=-1.08larrcolor(red)" in fourth quadrant"#
#rArr8-15ito(17,-1.08)#
