How do you convert #4sqrt3-4i# to polar form?

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How do you convert #4sqrt3-4i# to polar form?

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Answer 1 · 2016-11-09T21:50:33

#r=8#
#theta=-pi/6#

Explanation:

#4root2(3)-i4# is a vector on the Gauss plane whose length is
#r=root2(4^2*3+4^2)=8# and the angle referred to the real positive semi axis is #arctan(-1/root2(3))=-pi/6#

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How do you convert #4sqrt3-4i# to polar form?

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