How do you convert # 3x+2y=16# to polar form?

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How do you convert # 3x+2y=16# to polar form?

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Answer 1 · 2016-04-11T12:16:18

In polar form : #3 cos theta+4sin theta=16/r#

Explanation:

In polar form we know #r^2=x^2+y^2 ; x=rcostheta ;y =rsin theta and theta=tan^-1(y/x)# So # 3*r*cos theta+4*r*sin theta=16 or 3 cos theta+4sin theta=16/r#[Ans]

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How do you convert # 3x+2y=16# to polar form?

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