How do you convert $-345.12^circ$ to $D^circM'S''$ form?

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Answer 1 · 2018-03-21T04:05:15

$-345.12^@ = -(345^@ 7min 12sec)$

Conversion table for degrees $(@$ ), minutes (') & seconds (") :

$60^" = 1^', 60' = 1^@$

Given $-345 . 12^@$

$-345.12^@ = -345 -(0.12 ) = -345^@ - ((12/(10cancel(0))) * (6cancel0))^'$

$=> -345^@ + (- 72/10)' = -345^@ - 7' - (2/(1cancel(0)) *(6cancel0))"$

$=> -345^@ - 7' - 12sec = -345^@ 7' 12$ "

How do you convert -345.12^circ-345.12^circ to D^circM'S''D^circM'S'' form?