How do you convert 3 sqrt2 - 3 sqrt 2i to polar form?

1 Answer
Binayaka C.
Apr 17, 2016

In Polar form the equation is 6(cos(-0.785)+isin(-0.785))

Explanation:

Z=3sqrt2-3sqrt2i so Modulas Z=sqrt((3sqrt2)^2+(-3sqrt2)^2) =6
Argument z = theta = tan^-1(-(3sqrt2)/(3sqrt2))=tan_1(-1)=-0.785 radian So in Polar form the equation is 6(cos(-0.785)+isin(-0.785))

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