How do you convert #-3-3i# to polar form?

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How do you convert #-3-3i# to polar form?

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Answer 1 · 2016-05-26T10:19:31

In polar form the equation is #Z=3sqrt2(cos 225 +isin225)#

Explanation:

Let #Z= -3 -3i ;# Modulas #Z: r =sqrt((-3)^2+(-3)^2)=3sqrt2 #
Argument #Z; theta = 180^0 + tan^-1(3/3) = 180+45=225^0 (180^0# added as the point lies in 3rd quadrant). In polar form the equation is #Z=3sqrt2(cos 225 +isin225)#[Ans]

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How do you convert #-3-3i# to polar form?

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