How do you convert #3 + 3i# to polar form?
1 Answer
Apr 26, 2016
Explanation:
Using the formulae that links Cartesian to Polar coordinates.
#• r^2 = x^2+y^2 rArr r=sqrt(x^2+y^2)#
#• theta = tan^-1(y/x) # here x = 3 and y = 3
#rArr r = sqrt(3^2+3^2)=sqrt18 = 3sqrt2# and
# theta = tan^-1(3/3)=tan^-1(1)=pi/4#
#rArr 3 + 3i = (3sqrt2, pi/4)" in polar form "#
