How do you convert #2x+y=5# to polar form?

1 Answer
Jim G.
Jul 24, 2016

#r=5/(2costheta+sintheta)#

Explanation:

To convert from #color(blue)"cartesian to polar form"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta , y=rsintheta)color(white)(a/a)|)))#
and substituting into the equation.

#2(rcostheta)+rsintheta=5#

#rArr2rcostheta+rsintheta=5#

#rArrr(2costheta+sintheta)=5#

#rArrr=5/(2costheta+sintheta)" is the polar form"#

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