How do you convert #-2x + 6y = 7# to polar form?

1 Answer
Jim G.
Jul 9, 2016

#r=7/(6sintheta-2costheta)#

Explanation:

To convert from #color(blue)"cartesian to polar form"#

#color(orange)"Reminder"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta,y=rsintheta)color(white)(a/a)|)))#

Substituting into cartesian equation

#rArr-2(rcostheta)+6(rsintheta)=7#

#rArr-2rcostheta+6rsintheta=7#

#rArrr(6sintheta-2costheta)=7#

#rArrr=7/(6sintheta-2costheta)" is the polar form"#

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