How do you convert 27.6 g Ar to atoms?

2 Answers
anor277
Jun 6, 2016

Well, I know there are "Avogadro's number" of "Ar" atoms in a mass of 39.95*g.

Explanation:

Thus "Argon atoms" = (27.6*g)/(39.95*g*mol^-1)xx6.022xx10^23" argon atoms "mol^-1 = ??" argon atoms"

BRIAN M.
Jun 6, 2016

4.15x10^23 atoms of Argon

Explanation:

To change 27.6 g of Argon to atoms we begin by converting the grams of Argon to moles using a conversion factor of 1 mole equal to the mass of Argon from the periodic table.

27.6 cancel(g) ((1mol)/(39.95cancelg))=0.69 mol

Now convert moles to atoms using Avogadro's number of 6.02x10^23

0.69cancel(mol)((6.02x10^23atms)/(1cancel(mol)))=

4.15x10^23 atoms of Argon

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