How do you convert 2.54 moles magnesium carbonate to formula units?

1 Answer
anor277
Apr 18, 2016

By use of "Avogadro's Number", N_A=6.022xx10^23*mol^-1

Explanation:

It is a fact that in 1 mol of stuff there are 6.022xx10^23 individual items of that stuff.

Thus in 2.54 mol MgCO_3, there are 2.54 xx N_A individual formula units. What is the mass of this quantity?

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