How do you convert #1 - (sqrt3)i# to polar form?

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How do you convert #1 - (sqrt3)i# to polar form?

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Answer 1 · 2016-11-30T12:11:34

In polar form expressed as # 2(cos300+isin300)#

Explanation:

Let #Z=1- (sqrt3)i # ; Modulus #|Z|=(sqrt(1^2+ (-sqrt3)^2)) =2 ; tan theta = sqrt (-3)/1 or tan theta = sqrt (-3) #Argument # theta =tan^-1(sqrt (-3)) = -60^0 or 300^0#.

In polar form expressed as # |Z|*(costheta+isin theta) or2(cos300+isin300)#[Ans]

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How do you convert #1 - (sqrt3)i# to polar form?

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