How do you convert #1 + i sqrt(3)# to polar form?
1 Answer
Jun 7, 2016
Explanation:
Using the formulae that link Cartesian to Polar coordinates.
#•r=sqrt(x^2+y^2)#
#•theta=tan^-1(y/x)# here x = 1 and y
#=sqrt3#
#rArrr=sqrt(1^2+(sqrt3)^2)=sqrt4=2# and
#theta=tan^-1(sqrt3)=pi/3# Thus
#(1,sqrt3)=(2,pi/3)" in polar form"#
