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How do you convert #1 - 3i# to polar form?

1 Answer

sankarankalyanam

Jun 24, 2018

#color(purple)("Polar form "= (r, theta) = (3.1623, 288.43^@#

Explanation:

#z = 1 - i 3#

#r = sqrt (1^2 + (-3)^2) = sqrt 10 = 3.1623#

#theta = tan ^(-1) (-3/1) = -71.57^@ = 288.43^@, " as point lies in IV quadrant"#

#color(purple)("Polar form "= (r, theta) = (3.1623, 288.43^@#

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