How do you condense #ln2 + ln6 - (1/2)ln9#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Shwetank Mauria Jul 30, 2016 #ln2+ln6-(1/2)ln9=ln4# Explanation: We can use #lnx+lny=lnxy#, #lnx-lny=ln(x/y)# and #1/nlnx=ln(root(n)x)# Hence, #ln2+ln6-(1/2)ln9# = #ln(2xx6)-ln(sqrt9)# = #ln12-ln3# = #ln(12/3)=ln4# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 7179 views around the world You can reuse this answer Creative Commons License