How do you condense #2log_3 (x) + 5 log_3 (y) - 4log_3 (z)#?

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How do you condense #2log_3 (x) + 5 log_3 (y) - 4log_3 (z)#?

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Answer 1 · 2016-03-22T19:41:01

#2log_3 x +5 log _3 y - 4 log _3 z##=log((x^2y^5)/(z^4))#

Explanation:

#2log_3 x +5 log _3 y - 4 log _3 z#
#=log_3 x^2 + log_3 y^5-log_3 z^4#-> use properties#log_b(xy)=log_b x+log_by and log_b(x/y) =log_b x-log_b y#
#=log((x^2y^5)/(z^4))#

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How do you condense #2log_3 (x) + 5 log_3 (y) - 4log_3 (z)#?

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