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How do you condense #2ln8+5ln(z-4)#?

1 Answer

MathFact-orials.blogspot.com

Jan 11, 2017

#ln(8^2(z-4)^5)#

Explanation:

We have:

#2ln8+5ln(z-4)#

We can use the rule that #xlny=lny^x# to rewrite this:

#ln8^2+ln(z-4)^5#

We can then use the rule that #lnA + lnB=ln(AB)# to rewrite:

#ln(8^2(z-4)^5)#

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