How do you condense #2 ln x + 3 ln y - 6 ln z#?

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Answer 1 · 2018-04-29T18:47:09

#ln((x^2y^3)/z^6)#

Laws/Properties of logarithms:

#log_am^n=nlog_am#

#log_a(m/n)=log_am-log_an#

#log_amn=log_am+log_an#

Condensing the expression:

#lnx^2+lny^3-lnz^6#

#lnx^2y^3-lnz^6#

#ln((x^2y^3)/z^6)#