How do you condense #2/3log_7(z-2)#?
1 Answer
Mar 16, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x^nhArrnlog_b x#
#rArr2/3log_7(z-2)=log_7(z-2)^(2/3)#
