How do you condense #1/3log_(2)27 - log_(2)9 #? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer A. S. Adikesavan May 18, 2016 #- log3/log 2=-ln 3/ln 2=-1.585#, nearly. Explanation: Use #log_b (m/n)=log_b m - log_b n, nlog_b a =log_b(a^n)# and #log_b a = log a/log b = ln a/ln b#. Here, #(1/3)log_2 27-log_2 9=log_2(27^(1/3)) - log_2 9# #=log_2 3 - log_2 9=log_2(3/9)=log_2(1/3)# #=-log_2 3=-log 3/log 2=-ln 3/ln 2=-1.585#, nearly Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1455 views around the world You can reuse this answer Creative Commons License