How do you condense $1/3log_(2)27 - log_(2)9$ ?

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Answer 1 · 2016-05-18T02:19:53

$- log3/log 2=-ln 3/ln 2=-1.585$ , nearly.

Use $log_b (m/n)=log_b m - log_b n, nlog_b a =log_b(a^n)$ and

$log_b a = log a/log b = ln a/ln b$ .

Here, $(1/3)log_2 27-log_2 9=log_2(27^(1/3)) - log_2 9$

$=log_2 3 - log_2 9=log_2(3/9)=log_2(1/3)$

$=-log_2 3=-log 3/log 2=-ln 3/ln 2=-1.585$ , nearly

How do you condense 1/3log_(2)27 - log_(2)9 1/3log_(2)27 - log_(2)9 ?