How do you condense $\frac{1}{3} {log}_{2} 27 - {log}_{2} 9$ $1/3log_(2)27 - log_(2)9$ ?

Question

How do you condense $\frac{1}{3} {log}_{2} 27 - {log}_{2} 9$ $1/3log_(2)27 - log_(2)9$ ?

1 Answer

Impact of this question

1681 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-18T02:19:53

$- \frac{log 3}{log 2} = - \frac{ln 3}{ln 2} = - 1.585$ $- log3/log 2=-ln 3/ln 2=-1.585$ , nearly.

Explanation:

Use ${log}_{b} (\frac{m}{n}) = {log}_{b} m - {log}_{b} n, n {log}_{b} a = {log}_{b} (a^{n})$ $log_b (m/n)=log_b m - log_b n, nlog_b a =log_b(a^n)$ and

${log}_{b} a = \frac{log a}{log b} = \frac{ln a}{ln b}$ $log_b a = log a/log b = ln a/ln b$ .

Here, $(\frac{1}{3}) {log}_{2} 27 - {log}_{2} 9 = {log}_{2} (27^{\frac{1}{3}}) - {log}_{2} 9$ $(1/3)log_2 27-log_2 9=log_2(27^(1/3)) - log_2 9$

$= {log}_{2} 3 - {log}_{2} 9 = {log}_{2} (\frac{3}{9}) = {log}_{2} (\frac{1}{3})$ $=log_2 3 - log_2 9=log_2(3/9)=log_2(1/3)$

$= - {log}_{2} 3 = - \frac{log 3}{log 2} = - \frac{ln 3}{ln 2} = - 1.585$ $=-log_2 3=-log 3/log 2=-ln 3/ln 2=-1.585$ , nearly

Science

Math

Humanities

... and beyond

How do you condense $\frac{1}{3} {log}_{2} 27 - {log}_{2} 9$ $1/3log_(2)27 - log_(2)9$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you condense 1/3log_(2)27 - log_(2)9 13log227−log291/3log_(2)27 - log_(2)9 ?

1 Answer

Explanation:

Related questions

Impact of this question

How do you condense $\frac{1}{3} {log}_{2} 27 - {log}_{2} 9$ $1/3log_(2)27 - log_(2)9$ ?