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How do you compute the value of #int 1/x dx# of #[1,10]#?

1 Answer

Nov 24, 2016

Using the fundamental theorem of Calculus

Explanation:

#int_a^b f(x)dx = F(b) - F(a)#
where #(dF(x))/dx = f(x)#

As:

#int_1^"10"1/x dx = int_1^"10" d((ln(x)))/dx = ln(x) |_1^"10"= ln(10) -ln(1) = ln(10)#

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