How do you combine $\frac{x + 5}{x^{2} - 4 x + 3} - \frac{10 - 2 x}{x^{2} - 5 x + 6}$ $(x+5)/(x^2-4x+3) - (10-2x)/(x^2-5x+6)$ ?

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Answer 1 · 2018-05-29T15:04:25

$\Rightarrow \frac{3 x - 1}{(x - 1) (x - 3)}$ $color(blue)(=> (3x-1) / ((x-1)(x-3)$

$\frac{x + 5}{x^{2} - 4 x + 3} - \frac{10 - 2 x}{x^{2} - 6 x + 5}$ $(x+5)/(x^2-4x + 3) - (10-2x)/(x^2-6x +5)$

$=>(x+5) / ((x-1) (x-3)) .+ (2 * color(red)(cancel((x-5)))) / ((x-1) color(red)(cancel((x-5))$

$=> ((x+5) + 2(x-3))/ ((x-1)(x-3))$

$color(blue)(=> (3x-1) / ((x-1)(x-3)$

How do you combine (x+5)/(x^2-4x+3) - (10-2x)/(x^2-5x+6)x+5x2−4x+3−10−2xx2−5x+6(x+5)/(x^2-4x+3) - (10-2x)/(x^2-5x+6)?