How do you combine and simplify $sqrt(25/128)$ ?

Question

4201 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-05T19:51:47

$[sqrt25]/(sqrt128)=5/(sqrt64sqrt2)=5/(8sqrt2)$

You should multiply top and bottom by $sqrt2$ to rationalise the fraction.

$5/(8sqrt2)xx(sqrt2)/sqrt2$

$(5sqrt2)/(8sqrt4)=(5sqrt2)/16$

How do you combine and simplify sqrt(25/128)sqrt(25/128)?