How do you calculate the theoretical and percent yields for this experiment?
Aluminum burns bromine, producing aluminum bromide:
#2Al (s) + 3Br_2 (l) -> 2AlBr_3 (s)#
in a certain experiment, 6.0 g aluminum was reacted with an excess of bromine to yield 50.3g aluminum bromide.
Aluminum burns bromine, producing aluminum bromide:
in a certain experiment, 6.0 g aluminum was reacted with an excess of bromine to yield 50.3g aluminum bromide.
1 Answer
Aug 15, 2016
Aluminum reduces bromine to give the salt in approx. 85% yield.
Explanation:
From your stoichiometrically balanced equation you note the 1:1 equivalence between moles of metal, and moles of salt: one mole of aluminum yields one mole of alumium tribromide given 100% yield.
Had all the metal reacted, there would be
Thus yield