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How do you calculate the initial pressure this situation: a sealed container of gas is squashed, reducing the volume from 0.5 #m^3# to 0.25 #m^3#, with a final pressure of 120 kPa?

1 Answer

Sep 13, 2017

Well, we use old Boyle's law.....#PV=k#, given constant temperature, and CONSTANT amount of gas.....and gets #P_1=60*kPa#.

Explanation:

And since #PV=k#, and thus for a PISTON at constant temperature, we write.....

#P_1V_1=P_2V_2#.............

And we solve for #P_1=(120*kPaxx0.25*m^3)/(0.5*m^3)=??*kPa#.

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