How do you calculate the enthalpy change for the reaction 2C_8H_18(l) + 17O_2(g) -> 16CO(g) + 18H_2O(l)? DeltaH^o"_(rxn) =?

Given;
2C_8H_18(l) + 17O_2(g) -> 16CO(g) + 18H_2O(l) DeltaH^o"_(rxn) = -11,020 kJ
2CO(g) + O_2(g) -> 2CO_2(g) DeltaH^o"_f = -566.0 kJ

1 Answer
anor277
Dec 11, 2016

Are you sure you have copied the question down correctly?

Explanation:

You want DeltaH for:

2C_8H_18(l) + 17O_2(g) rarr 16CO(g) + 18H_2O(l), and then you give us the thermodynamic reaction for precisely this equation. I suspect you want the parameters for the complete combustion of octane:

C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)

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