How do you calculate the change in Gibbs free energy (∆G) for the following reactions at 25 °C?
#Ca(s) + 2H_2O(l) → Ca(OH)_2(s) + H_2(g)#
∆H = -411.6 kJ/mol
∆S = 31.8 J/mol∙K?
∆H = -411.6 kJ/mol
∆S = 31.8 J/mol∙K?
1 Answer
Apr 25, 2016
You can do it like this:
Explanation:
Use this relationship which arises from the 2nd law of thermodynamics:
Putting in the values: