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How do you calculate #sinh^2(.55)#?

1 Answer

Shwetank Mauria

Oct 11, 2016

#sinh^2(0.55)=0.33426#

Explanation:

As #sinhx=(e^x-e^(-x))/2#,

#sinh(0.55)=(e^0.55-e^(-0.55))/2#

= #(1.733253-0.57695)/2#

= #1.156303/2#

and #sinh^2(0.55)=(1.156303/2)^2#

= #0.5781515^2=0.33426#

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