How do you calculate Log_sqrt(17)152? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer A. S. Adikesavan Aug 3, 2016 2 (log 152/log 17)= 3.5464, nearly. Explanation: Use log_b a=log a/log b. log_sqrt 17 152 =log 157/logsqrt 17 #=log 167/log(17^(1/2)) =2 (log 152/log 17)=3.5464, nearly. Answer link Related questions What is the exponential form of log_b 35=3? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is log_b 1? What are some identity rules for logarithms? What is log_b b^x? What is the reciprocal of log_b a? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1613 views around the world You can reuse this answer Creative Commons License