How do you calculate #log_8 7.9# with a calculator?

1 Answer
Shwetank Mauria
Sep 6, 2016

#log_8 7.9=0.9939#

Explanation:

Let #log_ba=x#. Hence #b^x=a# and log (to the base #10#) on both sides, we get

#xlogb=loga# or #x=loga/logb#

Hence #log_ba=loga/logb# and

#log_8 7.9=log7.9/log8#

= #0.8976/0.9031#

= #0.9939#

Related questions
See all questions in Functions with Base b
Impact of this question
1480 views around the world
You can reuse this answer
Creative Commons License