How do you calculate #Log_8 2#?

1 Answer
Apr 8, 2016

The value is #1/3#

Explanation:

You have to answer a question "To what power do I have to raise #8# to get #2#?". Since #2# is a cubic root of #8# you have to raise #8# to the power of #1/3#.

For every positive real number #a# and a natural #n>=2# you can write that:

#root(n)(a)=a^(1/n)#

So the value is #1/3#