How do you calculate #log_5 2.4# with a calculator? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Matt B. Nov 22, 2016 #log_bA=log(A)/log(b)# So, you would punch in: #log(2.4)/log(5)=#"Lorem Ipsum" Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1703 views around the world You can reuse this answer Creative Commons License