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How do you calculate # log_3(54)#?

1 Answer

A. S. Adikesavan

May 14, 2016

#log 2/log 3 + 3=3.631#, nearly.

Explanation:

For long-term-memory:

#log_b a=log_c a/log_c b=log a/log b=ln a/ln b#

Here,

#log_3 54= log 54/log 3#

#=log(2 (3^3))/log 3=(log 2 + 3 log 3)/log 3=log 2/log 3 + 3#

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