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How do you calculate #Log_2(2)#?

1 Answer

Shwetank Mauria

Jul 19, 2016

#log_2(2)=1#

Explanation:

An expression in exponential form #a^n=b# is written as #log_ab=n#.

Now #a^1=a# for all #a#, hence #log_a(a)=1#. Hence,

#log_2(2)=1# as #2^1=2#

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