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How do you calculate #(2+3i)/(-3-2i)#?

1 Answer

Feb 18, 2017

# -12/13 -5/13i#

Explanation:

Use the conjugate of the denominator to multiply by one:
#(2+3i)/(-3-2i) = (2+3i)/(-3-2i) * (-3+2i)/(-3+2i) = (-6+4i-9i+6i^2)/(9-4i^2)#

Remember that #i^2 = -1#

Simplify and combine like-terms :
#(-6+4i-9i-6)/(9+4) =(-12-5i)/13 = -12/13 -5/13i#

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