How do you calculate (2+3i)/(-3-2i)2+3i−3−2i?

1 Answer
marfre
Feb 18, 2017

-12/13 -5/13i−1213−513i

Explanation:

Use the conjugate of the denominator to multiply by one:
(2+3i)/(-3-2i) = (2+3i)/(-3-2i) * (-3+2i)/(-3+2i) = (-6+4i-9i+6i^2)/(9-4i^2)2+3i−3−2i=2+3i−3−2i⋅−3+2i−3+2i=−6+4i−9i+6i29−4i2

Remember that i^2 = -1i2=−1

Simplify and combine like-terms :
(-6+4i-9i-6)/(9+4) =(-12-5i)/13 = -12/13 -5/13i−6+4i−9i−69+4=−12−5i13=−1213−513i

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