How do you add $(x^2+2x)/(12x+54) - (3-x)/(8x+36)$ ?

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Answer 1 · 2015-05-19T05:09:14

Factorize

$=(x^2+2x)/(6(2x+9))-(3-x)/(4(2x+9))$
$=1/(2(2x+9))*{(x^2+2x)/3-(3-x)/2}$

$=1/(4x+18)*{(2(x^2+2x)-3(3-x))/6}$

$=1/(4x+18)*{(2x^2+4x-9+9x)/6}$

$=1/(4x+18)*{(2x^2+13x-9)/6}$
$=(2x^2+13x-9)/(24x+108)$

How do you add (x^2+2x)/(12x+54) - (3-x)/(8x+36)(x^2+2x)/(12x+54) - (3-x)/(8x+36)?