How do you add #(8-3i)+(7+4i)# in trigonometric form?

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Answer 1 · 2018-05-19T05:29:39

#(sqrt226, tan(1/15))#

If you add them together you get:

#15 + i#

I'm not sure what you mean "trigonometric form" but to convert to polar form #(r, theta)# you have

Standard complex form: #ax +bi#

#r = sqrt(a^2+b^2)#

#r = sqrt(15^2+1^2)#

#r=sqrt226#

#theta = tan(b/a)#

#theta = tan(1/15)#