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How do you add #(5+4i)+(-2-i)# in trigonometric form?

1 Answer

May 29, 2016

#-sqrt(41/5) (cos theta+isin theta)#, where #theta=tan^(-1) (3/14)or arctan(3/14)#

Explanation:

#(5+4i)/(-(2+i))= ((5+4i)(2-i))/(-(2+i)(2-i))#

=#(14+3i)/(-5) = -1/5 (14+3i)#

=#-1/5 *sqrt205 ( 14/sqrt205 +3/sqrt205 i)#

= #-sqrt(41/5) (cos theta+isin theta)#, where #theta=tan^(-1) (3/14)or arctan(3/14)#

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