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How do you add #(-3+i) + (4+6i)#?

1 Answer

Mar 29, 2018

#1+7i#. See explanation below

Explanation:

The addition in #CC# is defined by

#(a+bi)+(c+di)=(a+c)+(b+d)i#. The two complex numbers addition consists in adding real parts and imaginary parts separately.

In our case

#(-3+i)+(4+6i)=(-3+4)+(1+6)i# because the imaginary part of first complex number is 1. Then we have:

#(-3+4)+(1+6)i=1+7i#

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