How do you add $(2 - 5 i) + (7 - i)$ $(2-5i)+(7-i)$ in trigonometric form?

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Answer 1 · 2018-03-22T23:44:00

$9 - 6 i$ $9-6i$

We define the addition of two complex numbers $a + b i$ $a+bi$ and $c + d i$ $c+di$ as follows

$(a+bi)+(c+di):=(a+c)+(b+d)i$

So

$(2-5i)+(7-i)=(2+7)+(-5-1)i=9-6i$

How do you add (2-5i)+(7-i)(2−5i)+(7−i)(2-5i)+(7-i) in trigonometric form?