How do the stereoisomers of 2-bromo-3-hexene arise?

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How do the stereoisomers of 2-bromo-3-hexene arise?

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Answer 1 · 2016-05-28T09:18:37

4 types of stereoisomers of 2-bromo-3-hexene as shown below

Explanation:

self drawn
In 2-bromohex-3-ene $(C H_{3} C^{*} H (B r) C H = C H C H_{2} C H_{3})$ $(CH_3C^"*"H(Br)CH=CHCH_2CH_3)$ there exist one chiral carbon atom $(C_{2})$ $(C_2)$ and one unsymmetrical $C = C$ $C=C$ .
Due to the presence of one chiral carbon atom $(C_{2})$ $(C_2)$ it exhibits R and S stereo isomerism and due to the presence of one unsymmetrical $C = C$ $C=C$ ,starting at $C_{3}$ $C_3$ , it exhibits E and Z isomerism . So $2 \times 2 = 4$ $2xx2=4$ combinations make 4 types of stereoisomers. They are shown with their names in above figures.

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How do the stereoisomers of 2-bromo-3-hexene arise?

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