How do I solve this?

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How do I solve this?

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Answer 1 · 2016-05-16T09:23:42

$/_MPL=80^o$

Explanation:

Join line $MN$ and now examine $DeltaMNP$ .

As $m hat(ML)=175^o$ and $m hat(ON)=15^o$

$/_MPL=/_MNL-/_PMN$ ,

as exterior angle is equal to sum of interior opposite angles.

Now $/_MNL=1/2xx(m hat(ML))=1/2xx175^o$ and

$/_PMN=1/2xx(m hat(ON))=1/2xx15^o$

Hence $/_MPL=/_MNL-/_PMN$

= $1/2xx175^o-1/2xx15^o$

= $1/2xx(175^o-15^o)$

= $80^o$

Answer 2 · 2016-05-16T10:09:54

$angle MPL = (angle ML)/2-(angle ON)/2 = 80^o$

Explanation:

$angle OMN = (angle ON)/2$
$angle MNL = (angle ML)/2$
$angle MPL + pi-angle MNL+angle OMN=pi$
Solving for $angle MPL = (angle ML)/2-(angle ON)/2 = 80^o$

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