How do I solve #log_(2/3) (8/27)#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Nityananda Oct 15, 2017 3 Explanation: Let , #m =log_"(2/3)" (8/27)# #rArr (2/3)^m = 8/27# #rArr (2/3)^m = (2^3)/(3^3)# #rArr (2/3)^m = (2/3)^3# #rArr m = 3# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 4250 views around the world You can reuse this answer Creative Commons License