How do I graph $16x^2-9y^2+32x+18y-137=0$ algebraically?

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Answer 1 · 2015-09-26T18:16:16

Ellipse centered at (-1,1) and semi major axis of 4 unitsalong y axisand semi minor axis of 3 units.

Write the equation in standard form by completing the squares,

$16x^2 +32x -9y^2 +18y -137=0$

$16(x^2 +2x +1) -9(y^2 -2y +1) -16 +9-137=0$

$16(x+1)^2 -9(y-1)^2=144$

$(x+1)^2 /3^2 - (y-1)^2 /4^2 =1$

This is an ellipse with its centre at (-1,1), with semi-major axis of 4 units along y axis and semi-minor axis of 3 units along x axis

How do I graph 16x^2-9y^2+32x+18y-137=016x^2-9y^2+32x+18y-137=0 algebraically?