How do I find the value of tan 6π? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer VNVDVI Apr 11, 2018 tan(6pi)=tan(pi)=0 Explanation: Tangent has a period of pi, meaning tan(a)=tan(a+npi) where n is any positive or negative integer. So, tan(6pi)=tan(6pi-5pi)=tan(pi)=0 Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 6023 views around the world You can reuse this answer Creative Commons License