# How do I find the derivative of k(a)=sin^5acos^4a?

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How do I even find f'x for sin^5a and cos^4a? I would use the product rule, but I'm lost on just what the derivatives of the separate parts are.

How do I even find f'x for sin^5a and cos^4a? I would use the product rule, but I'm lost on just what the derivatives of the separate parts are.

##### 1 Answer

Apr 30, 2018

#### Explanation:

- Let
#g(a)=sin^5a#

- Let
#h(a)=cos^4a#

**Substitute**