How do I find the asymptotes of $y=-1/x^2$ ?

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Answer 1 · 2015-09-13T20:28:34

Horizontal asymptote at: $y = 0$

Vertical asymptote at: $x= 0$

$y=-1/x^2$

The horizontal asymptote is at : $lim(x to +-oo$ ) $(y)$

So in this case:

$lim(x to +-oo$ ) $(-1/x^2) =>$

as x tends to infinity the denominator keeps getting larger and

larger forcing the fraction to tend to zero, hence: the horizontal

asymptote is at $y = 0$ , AKA the x-axis

The vertical asymptote(s) are the at the value(s) of x that make the

function $f(x) = y$ undefined hence the vertical asymptote in this

case is at:

$x = 0$ , AKA the y-axis.

How do I find the asymptotes of y=-1/x^2y=-1/x^2?