How do a construct an exponential equation given (0, -1) and (2, -36)?

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Answer 1 · 2015-12-30T00:51:54

Start with the general equation for an exponential ...

#y=ab^x#

Now solve for the constants a and b by inserting the values for x,y

#(0,-1): -1=ab^0=a#

So, now we know that #a=-1#. Continue to solve for b ...

#(2,-36): -36=(-1)b^2 rarrb^2=36rarrb=6#

Finally, insert a and b ..

#y=(-1)6^x#

hope that helped