How can you use trigonometric functions to simplify # 9 e^( ( 5 pi)/3 i ) # into a non-exponential complex number?
1 Answer
Mar 5, 2016
Explanation:
Using
#color(blue)" Euler's relationship " # which states
#re^(theta i) = r(costheta + isintheta) # here r = 9 and
#theta = (5pi)/3 #
#rArr9e^((5pi)/3 i) = 9 [cos((5pi)/3) + isin((5pi)/3) ]#
